the identifier function

Hello, I was learning about the identifier function and came across an observation. Please see the scenarios below:

In this first scenario I searched for the word "hi" and it appears only once in 1 object with an ID entitled "alpha_1"

Object o

print identifier(o)

This would print "alpha_1"

However, lets say I do a search for the word "hello" . This time however, this word appears in objects "alpha_4" and "alpha_5"

if I do this:

Object o

print identifier(o)

This would print "alpha_4alpha_5"

If you notice the second example, it does identify both positions in which the word is found, however, it appends that result as one single string. Does anyone know how I could split this apart so that it would identify this as 2 seperate results instead of just 1 big concatenation?

For example, I would want it to state

"alpha_4"

"alpha_5"

Thanks.

Re: the identifier function
llandale - Fri Aug 16 13:44:12 EDT 2013

Generally end your print statements with an EOL:

• print identifier(o) "\n"
• print "This is a print statement ending in an EOL\n"
• print "There is no EOL here, so the next line will be on this line\t"   // after the tab
• print "Next Line\n"

This has nothing to do with the "identifier()" function.

-Louie